Szczegółowe wyjaśnienie:
[tex]b)\ \sqrt{15}\ i\ \sqrt{30}\\\\\sqrt{15}<\sqrt{16}=4\\\sqrt{30}>\sqrt{25}=5\\\\\boxed{4,\ 5}\\\\c)\ \sqrt{30}\ i\ \sqrt{85}\\\\\sqrt{30}<\sqrt{36}=6\\\sqrt{85}>\sqrt{81}=9\\\\\boxed{6,\ 7,\ 8,\ 9}\\\\d)\ \sqrt2\ i\ \sqrt5\\\\\sqrt2<\sqrt4=2\\\sqrt5>\sqrt4=2\\\\\boxed{2}[/tex]
Wytłumaczenie do a)
[tex]\sqrt{57}<\sqrt{64}=8\\\sqrt{102}>\sqrt{100}=10\\\\\boxed{8,\ 9,\ 10}[/tex]
