Odpowiedź:
[tex] \sin^{2} \alpha + \cos^{2} \alpha = 1[/tex]
[tex] tg \: \alpha = \frac{ \sin \alpha }{ \cos \alpha } [/tex]
[tex] \sin ^{2} \alpha + ( \frac{3}{5} )^{2} = 1 \\ \sin ^{2} \alpha = 1 - \frac{9}{25} \\ \sin ^{2} \alpha = \frac{16}{25} \: \: \: \: | \sqrt{} \\ \sin \alpha = \frac{4}{5} [/tex]
[tex] tg \: \alpha = \frac{4}{5} \div \frac{3}{5} \\ tg \: \alpha = \frac{4}{5} \times \frac{5}{3} \\ tg \: \alpha = \frac{4}{3} [/tex]
