Odpowiedź :
[tex]2x^{3}+3x^{2}+3x+1 =0\\\\2x^{3} +x^{2}+2x^{2}+x+2x+1 = 0\\\\x^{2}(2x+1) +x(2+1)+(2x+1) = 0\\\\(2x+1)(x^{2}+x+1) = 0\\\\2x+1 = 0\\\\2x = -1 \ \ /:2\\\\x = -\frac{1}{2}\\\\Lub\\\\x^{2}+x+1 = 0\\\\\Delta = 1-4 = -3 < 0, \ nie \ ma \ rozwiazan \ w \ zbiorze \ R\\\\\boxed{x = -\frac{1}{2}}[/tex]