Odpowiedź :
Odpowiedź:
[tex] | \frac{1}{3} - 0.3 | - | \frac{2}{3} - 0.7 | = \frac{1}{3} - 0.3 - ( - \frac{2}{3} + 0.7) = \frac{1}{3} - 0.3 + \frac{2}{3} - 0.7 = 1 - 1 = 0[/tex]
[tex] |1.5 - \sqrt{2} | + |1.4 - \sqrt{2} | = 1.5 - \sqrt{2} - 1.4 + \sqrt{2} = 0.1[/tex]
[tex](2 - \sqrt{5} ) |2 - \sqrt{5} | = (2 - \sqrt{5} )( - 2 + \sqrt{5} ) = - 4 + 2 \sqrt{5} + 2 \sqrt{5} - 5 = 4 \sqrt{5} - 9[/tex]
Z def. wartości bezwzględnej:
|x| = x dla x ≥ 0
|x| = -x dla x < 0
1.
[tex]\frac{1}{3} > 0,3, \ \ \frac{2}{3} < 0,7\\\\|\frac{1}{3}-0,3| -|\frac{2}{3}-0,7| = \frac{1}{3}-0,3 - (0,7-\frac{2}{3}) = \frac{1}{3}-0,3-0,7+\frac{2}{3} = 1-1 = 0[/tex]
2.
[tex]1,5 > \sqrt{2}, \ \ 1,4 < \sqrt{2}\\\\|1,5-\sqrt{2}|+|1,4-\sqrt{2}|=1,5-\sqrt{2}+(\sqrt{2}-1,4) = 1,5-\sqrt{2} +\sqrt{2}-1,4 = 0,1[/tex]
3.
[tex]2 < \sqrt{5}\\\\(2-\sqrt{5})|2-\sqrt{5}|=(2-\sqrt{5})(\sqrt{5}-2) = 2\sqrt{5}-4-5+2\sqrt{5} =4\sqrt{5} -9[/tex]