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[tex](-1\frac{2}{5})^2=(-\frac{1\cdot5+2}{5})^2=(-\frac{5+2}{5})^2=(-\frac{7}{5})^2=-\frac{7}{5}\cdot(-\frac{7}{5})=\frac{49}{25}=1\frac{24}{25}\\\\(-2\frac{1}{3})^2=(-\frac{2\cdot3+1}{3})^2=(-\frac{6+1}{3})^2=(-\frac{7}{3})^2=-\frac{7}{3}\cdot(-\frac{7}{3})=\frac{49}{9}=5\frac{4}{9}[/tex]
