Odpowiedź:
[tex]a)\ \ \frac{5}{7}-2\frac{3}{7}+1\frac{4}{7}=1\frac{9}{7}-2\frac{3}{7}=2\frac{2}{7}-2\frac{3}{7}=-\frac{1}{7}\\\\\\b)\ \ -\frac{5}{8}-1\frac{3}{8}+\frac{14}{15}=-1\frac{8}{8}+\frac{14}{15}=-2+\frac{14}{15}=-\frac{30}{15}+\frac{14}{15}=-\frac{16}{15}=-1\frac{1}{15}\\\\\\c)\ \ -8\frac{1}{2}+5\frac{1}{2}-3\frac{1}{3}=-3-3\frac{1}{3}=-6\frac{1}{3}[/tex]
[tex]d)\ \ \frac{3}{4}+(-\frac{1}{4})-2\frac{1}{2}=\frac{3}{4}-\frac{1}{4}-2\frac{1}{2}=\frac{2}{4}-2\frac{1}{2}=\frac{1}{2}-2\frac{1}{2}=-2\\\\\\e)\ \ 2\frac{2}{3}+(-1\frac{1}{6})+(-3\frac{1}{2})=2\frac{2}{3}-1\frac{1}{6}-3\frac{1}{2}=\frac{8}{3}-\frac{7}{6}-\frac{7}{2}=\frac{16}{6}-\frac{7}{6}-\frac{21}{6}=-\frac{12}{6}=-2[/tex]
[tex]f)\ \ -11+1\frac{3}{5}-(-10\frac{1}{10})=-11+1\frac{3}{5}+10\frac{1}{10}=-11+1\frac{6}{10}+10\frac{1}{10}=-11+11\frac{7}{10}=\frac{7}{10}[/tex]
