Odpowiedź :
Odpowiedź:
a)= 3^7 x 3^-2 x 3^5= 3^7-2+5=3^10
b)= 0,2^5= (1/5)^5= 1/3125
c)= (-1/4)^7= -1/16384
d)= 10^8: (-10) x (-10^7)= 10^14
Szczegółowe wyjaśnienie:
Licze na Naj
[tex]a) \ 3^{7}:3^{2}\cdot3^{5} = 3^{7-2}\cdot3^{5} = 3^{5}\cdot3^{5} = 3^{5+5} = 3^{10}\\\\\\b) \ 0,2^{4}\cdot0,2^{3}:0,2^{2} =0,2^{4+3}:0,2^{2} = 0,2^{7}:0,2^{2} = 0,2^{7-2} =0,2^{5}=(\frac{1}{5})^{5}\\\\\\c) \ (-\frac{1}{4})^{5}\cdot(-\frac{1}{4})^{4} :(-\frac{1}{4})^{2} =(-\frac{1}{4})^{5+4}:(-\frac{1}{4})^{2} = (-\frac{1}{4})^{9-2} =(-\frac{1}{4})^{7}\\\\\\d) \ (-10)^{8}:(-10)^{1}\cdot(-10)^{7} = (-10)^{8-1}\cdot(-10)^{7} = (-10)^{7}\cdot(-10)^{7} =(-10)^{14} =\\\\= 10^{14}[/tex]
Wykorzystano wzory:
[tex]a^{m}\cdot a^{n} = a^{m+n}\\\\a^{m}:a^{n} = a^{m-n}[/tex]