Odpowiedź:
[tex]a)\ \ (3-\sqrt{2})(\sqrt{2}-1)=3\sqrt{2}-3-\sqrt{4}+\sqrt{2}=4\sqrt{2}-3-2=4\sqrt{2}-5\\\\\\b)\ \ \sqrt{3}-(\sqrt{3}-5)(4+\sqrt{3})=\sqrt{3}-(4\sqrt{3}+\sqrt{9}-20-5\sqrt{3})=\sqrt{3}-(-\sqrt{3}+3-20)=\\\\=\sqrt{3}-(-\sqrt{3}-17)=\sqrt{3}+\sqrt{3}+17=2\sqrt{3}+17\\\\\\c)\ \ (\sqrt{5}-1)(\sqrt{5}+1)=\sqrt{25}+\sqrt{5}-\sqrt{5}-1=5-1=4\\\\lub\\\\(\sqrt{5}-1)(\sqrt{5}+1)=(\sqrt{5})^2-1^2=5-1=4[/tex]
[tex]d)\ \ (\sqrt{3}-2)(5+\sqrt{2})-\sqrt{6}=5\sqrt{3}+\sqrt{6}-10-2\sqrt{2}-\sqrt{6}=5\sqrt{3}-2\sqrt{2}-10[/tex]
