Odpowiedź :
Odpowiedź:
[tex]b)\ \ (\frac{1}{2})^3-(\frac{1}{3})^2=\frac{1}{8}-\frac{1}{9}=\frac{9}{72}-\frac{8}{72}=\frac{1}{72}\\\\c)\ \ 2^5-(3^2-3^3)=32-(9-27)=32-(-18)=32+18=50[/tex]
Odpowiedź:
[tex]b)\ \ (\frac{1}{2})^3-(\frac{1}{3})^2=\frac{1}{8}-\frac{1}{9}=\frac{9}{72}-\frac{8}{72}=\frac{1}{72}\\\\c)\ \ 2^5-(3^2-3^3)=32-(9-27)=32-(-18)=32+18=50[/tex]