Odpowiedź:
d)
2x + 1 = 2 - √3x
2x + √3x = 2 - 1
x(2 + √3) = 1
x = 1/(2 + √3) = (2 - √3)/(4 - 3)= (2 - √3)/1 = 2 - √3
e)
√5x - 3x = 1 - 5x
√5x - 3x + 5x = 1
√5x + 2x = 1
x(√5 + 2) = 1
x = 1/(√5 + 2) = (√5 - 2)/(5 - 4) = (√5 - 2)/1 = √5 - 2
f)
x(√3 + 1) = 2(x + 1)
√3x + x = 2x + 2
√3x + x - 2x = 2
√3x - x = 2
x(√3 - 1) = 2
x = 2/(√3 - 1) = 2(√3 + 1)/(3 - 1) = 2(√3 + 1)/2 = √3 + 1
