log3 27 + log4 16=
log 1/2 +log 2
daje naj ​


Odpowiedź :

[tex] log_{3}(27) = x \\ {3}^{x} = 27 \\ {3}^{x} = {3}^{3} \\ x = 3 \\ \\ log_{4}(16) = x \\ {4}^{x} = 16 \\ {4}^{x} = {4}^{2} \\ x = 2 \\ 3 + 2 = 5[/tex]

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[tex] log_{}( \frac{1}{2} ) + log_{}(2) = log_{}( \frac{1}{2} \times 2) = log_{}(1) = 0[/tex]