Obliczenia
[tex]-4(2x+0,5)=-4\cdot2x-4\cdot0,5=\underline{-8x-2}\\\\\frac{2}{3}(6y-15)=\frac{2}{3}\cdot6y-\frac{2}{3}\cdot15=\frac{12}{3}y-\frac{30}{3}=\underline{4y-10}[/tex]
