Od a) do d)
[tex]-1\frac{1}{4}\cdot(-4)=-\frac{5}{4}\cdot(-4)=5\\\\-6\frac{2}{3}:2=-\frac{20}{3}\cdot\frac{1}{2}=-\frac{10}{3}=-3\frac{1}{3}\\\\-0,2\cdot(-0,2)=0,04\\\\-3\frac{1}{3}\cdot(-3)=-\frac{10}{3}\cdot(-3)=10[/tex]
Od e) do h)
[tex](-3)^2\cdot\frac{1}{3}=9\cdot\frac{1}{3}=3\\\\(\frac{1}{3})^2\cdot(-9)=\frac{1}{9}\cdot(-9)=-1\\\\-6^2:\frac{1}{2}=-36\cdot2=-72\\\\3\frac{3}{4}:(-1,25)^2=\frac{15}{4}:(-\frac{5}{4})^2=\frac{15}{4}:\frac{25}{16}=\frac{15}{4}\cdot\frac{16}{25}=\frac{12}{5}=2\frac{2}{5}[/tex]
