Zadanie 1 tylko proszę pilnie

a) [tex]\sqrt{1,96 : 196} = \sqrt{\frac{196}{100} * \frac{1}{196}[/tex] [tex]= \sqrt{\frac{1}{100} } = \frac{1}{10}[/tex]
b) [tex]\sqrt[3]{(-1) : 125} = - \sqrt[3]{\frac{1}{125} } = - \frac{1}{5}[/tex]
c) [tex]\sqrt[3]{\frac{1}{8} : \frac{64}{27} } = \sqrt[3]{\frac{1}{8} * \frac{27}{64} } = \sqrt[3]{\frac{27}{512} } = \frac{3}{8}[/tex]