[tex]3^{5}\times3^{-8} = 3^{5+(-8)} = 3^{-3}=(\frac{1}{3})^{3} =\frac{1}{27}\\\\b) \ (\frac{5}{7})^{-6} \times(\frac{5}{7})^{4} = (\frac{5}{7})^{-6+4} = (\frac{5}{7})^{-2} = (\frac{7}{5})^{2} = \frac{49}{25} = 1\frac{24}{25}\\\\c) \ (2\frac{1}{3})^{5}\times(2\frac{1}{3})^{-3} = (2\frac{1}{3})^{5+(-3)} = (2\frac{1}{3})^{2} = (\frac{7}{3})^{2} = \frac{49}{9} = 5\frac{1}{9}[/tex]
[tex]d) \ 3^{4}\times3^{-3} = 3^{4+(-3)} = 3^{1} = 3\\\\d) \ 2^{3}\times2^{5}\times2^{-2}\times2^{2} = 2^{3+5-2+2} = 2^{8} = 256[/tex]
