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Proszę O Pomoc To Na Jutrzejszą Lekcje Matematyki class=

Odpowiedź :

Kontonawszystkoviz

zad. 1

[tex]b)(( - 3 {)}^{4} {)}^{5} = ( - {3)}^{20} = {3}^{20} [/tex]

[tex]d)( {5}^{3} {)}^{0} = {5}^{0} = 1 \\ e)( {x}^{2} {)}^{7} = {x}^{14} [/tex]

zad. 2

[tex]a)( {5}^{2} {)}^{6} = {5}^{12} \\ b)( {2}^{2} {)}^{15 } = {2}^{30} [/tex]

[tex]f)125 {}^{6} = ( {5}^{3} {)}^{6} = {5}^{18} [/tex]

zad. 3

[tex]b) {8}^{2} \times {4}^{5} = ( {2}^{3} {)}^{2} \times ( {2}^{2} {)}^{5} = {2}^{6} \times {2}^{10} = {2}^{16} [/tex]

[tex]d)3 {2}^{3} \times {2}^{2} \times {2}^{4} = ({2}^{5} {)}^{3} \times {2}^{2} \times {2}^{4} = {2}^{15} \times {2}^{2} \times {2}^{4} = {2}^{21} [/tex]

[tex]f)( {2}^{7} \div {2}^{4} {)}^{2} \times {2}^{6} = ( {2}^{3} {)}^{2} \times {2}^{6} = {2}^{6} \times {2}^{6} = {2}^{12} [/tex]

Odpowiedź:

Szczegółowe wyjaśnienie:

1.

b) ((-3)^4)^5 = 3^20

d) (5³)^0 = 5^0 = 1

e) (x²)^7 = x^14

2.

a) 25^6 = (5²)^6 = 5^12

b) 4^15 = (2²)^15 = 2^30

f) 125^6 = (5³)^6 = 5^18

3.

b) 8² * 4^5 = (2³)² * (2²)^5 = 2^6 * 2^10 = 2^16

d) 32³ * 2² * 2^4 = [(2)^5]³ * 2^6 = 2^15 * 2^6 = 2^21

f) (2^7 : 2^4)² * 2^6 = (2³)² * 2^6 = 2^6 * 2^6 = 2^12