Obliczenia
[tex]2^7\cdot5^7=(2\cdot5)^7=10^7\\\\(-3)^2\cdot17^2=(-3\cdot17)^2=(-51)^2=51^2\\\\(\frac{1}{2})^5\cdot(\frac{1}{5})^5=(\frac{1}{2}\cdot\frac{1}{5})^5=(\frac{1}{10})^5\\\\(-\frac{1}{3})^4\cdot(\frac{3}{5})^4=(-\frac{1}{3}\cdot\frac{3}{5})^4=(-\frac{1}{5})^4=(\frac{1}{5})^4[/tex]
Wykorzystany wzór
[tex]a^m\cdot b^m=(a\cdot b)^m[/tex]
