Odpowiedź:
2³/(∛2)¹² = 4²ˣ/(√2)²ˣ²
2³ * (√2)²ˣ² = 4²ˣ * (∛2)¹²
2³ * (2¹⁾²)²ˣ² = (2²)²ˣ * (2¹⁾³)¹²
2³ * 2ˣ² =2⁴ˣ * 2⁴
2³⁺ˣ² = 2⁴ˣ⁺⁴
3 + x² = 4x + 4
x² - 4x + 3 - 4 = 0
x² - 4x - 1 = 0
a = 1 ,b = - 4 , c = - 1
Δ = b² - 4ac = (- 4)² - 4 * 1 * ( - 1) = 16 + 4 = 20
√Δ = √20 = √(4 * 5) = 2√5
x₁ = (- b - √Δ)/2a = (4 - 2√5)/2= 2(2 - √5)/2 = 2 - √5
x₂ = ( - b + √Δ)/2a = (4 + 2√5)/2 = 2(2 + √5)/2 = 2 + √5
