Odpowiedź:
[tex](2\frac{2}{6}-\frac{2}{3})^2-2\frac{1}{5}=(2\frac{1}{3}-\frac{2}{3})^2-2\frac{1}{5}=(\frac{7}{3}-\frac{2}{3})^2-2\frac{1}{5}=(\frac{5}{3})^2-2\frac{1}{5}=\frac{25}{9}-2\frac{1}{5}=\\\\=2\frac{7}{9}-2\frac{1}{5}=2\frac{35}{45}-2\frac{9}{45}=\frac{26}{45}[/tex]
[tex]10-2\cdot(3\frac{1}{5}-2\frac{1}{4}\cdot\frac{1}{3})=10-2\cdot(3\frac{1}{5}-\frac{\not9^3}{4}\cdot\frac{1}{\not3_{1}})=10-2\cdot(3\frac{1}{5}-\frac{3}{4})=10-2\cdot(3\frac{4}{20}-\frac{15}{20})=\\\\=10-2\cdot(2\frac{24}{20}-\frac{15}{20})=10-2\cdot2\frac{9}{20}=10-\not2^1\cdot\frac{49}{\not20_{10}}=10-\frac{49}{10}=10-4\frac{9}{10}=\\\\=9\frac{10}{10}-4\frac{9}{10}=5\frac{1}{10}[/tex]
[tex](\frac{7}{3}-\frac{5}{12}+1\frac{1}{2}):(2\frac{3}{4}-\frac{5}{6})=(\frac{28}{12}-\frac{5}{12}+1\frac{6}{12}):(2\frac{9}{12}-\frac{10}{12})=(\frac{23}{12}+\frac{18}{12}):(1\frac{21}{12}-\frac{10}{12})=\\\\=\frac{41}{12}:1\frac{11}{12}=\frac{41}{12}:\frac{23}{12}=\frac{41}{\not12}\cdot\frac{\not12}{23}=\frac{41}{23}=1\frac{18}{23}[/tex]
Odpowiedź:
(2 2/6 - 2/3)² - 2 1/5 = (2 1/3 - 2/3)² - 2 1/5 = (1 4/3 - 2/3)² - 2 1/5 =
= (1 2/3)² - 2 1/5 = (5/3)² - 2 1/5 = 25/9 - 2 1/5 = 2 7/9 - 2 1/5 =
= 2 35/45 - 2 9/45 = 26/45
10 - 2 * (3 1/5 - 2 1/4 * 1/3) = 10 - 2 * (3 1/5 - 9/4 * 1/3) + = 10 - (3 1/5 - 3/4) =
= 10 - (3 4/20 - 15/20) = 10 - (2 24/20 - 15/20) = 10 - 2 9/20 = 7 11/20
(7/3 - 5/12 + 1 1/2) : (2 3/4 - 5/6) = (1 4/3 - 5/12 + 3/2) : (11/4 - 5/6) =
= (1 16/12 - 5/12 + 3/2) : (33/12 - 5/12) = (1 11/12 + 1 6/12) : 28/12 =
= 2 17/12 * 12/28 = 41/12 * 12/28 = 41/28 = 1 13/28
Szczegółowe wyjaśnienie:
