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proszę o pomoc w tym zadaniu

Proszę O Pomoc W Tym Zadaniu class=

Odpowiedź :

Cześć ;-)

Obliczenia

[tex]1] \ \frac{4}{\sqrt6}=\frac{4}{\sqrt6}\cdot\frac{\sqrt6}{\sqrt6}=\frac{4\sqrt6}{\sqrt{6^2}}=\frac{4\sqrt6}{6}=\frac{2\sqrt6}{3}\\\\2] \ \frac{2}{3\sqrt5}=\frac{2}{3\sqrt5}\cdot\frac{\sqrt5}{\sqrt5}=\frac{2\sqrt5}{3\sqrt{5^2}}=\frac{2\sqrt5}{3\cdot5}=\frac{2\sqrt5}{15}\\\\3] \ \frac{\sqrt2-1}{\sqrt2}=\frac{\sqrt2-1}{\sqrt2}\cdot\frac{\sqrt2}{\sqrt2}=\frac{2-\sqrt2}{\sqrt{2^2}}=\frac{2-\sqrt2}{2}[/tex]

Pozdrawiam!

Magdaviz

Odpowiedź:

[tex]1)\ \ \dfrac{4}{\sqrt{6}}=\dfrac{4}{\sqrt{6}}\cdot\dfrac{\sqrt{6}}{\sqrt{6}}=\dfrac{\not4^2\sqrt{6}}{\not6_{3}}=\dfrac{2\sqrt{6}}{3}\\\\\\2)\ \ \dfrac{2}{3\sqrt{5}}=\dfrac{2}{3\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}=\dfrac{2\sqrt{5}}{3\sqrt{5}\cdot\sqrt{5}}=\dfrac{2\sqrt{5}}{3\cdot5}=\dfrac{2\sqrt{5}}{15} \\\\\\3)\ \ \dfrac{\sqrt{2}-1}{\sqrt{2}}=\dfrac{\sqrt{2}-1}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}=\dfrac{(\sqrt{2}-1)\cdot\sqrt{2}}{2}=\dfrac{2-\sqrt{2}}{2}[/tex]

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