Odpowiedź:
[tex]a)\ \ 1\frac{1}{3}+3\frac{2}{3}=4\frac{3}{3}=5\\\\b)\ \ -3\frac{2}{7}+7\frac{6}{7}=7\frac{6}{7}-3\frac{2}{7}=4\frac{4}{7}\\\\c)\ \ 2\frac{3}{4}-3\frac{1}{2}=\frac{11}{4}-\frac{7}{2}=\frac{11}{4}-\frac{14}{4}=-\frac{3}{4}\\\\d)\ \ -1\frac{1}{4}-2\frac{2}{3}=-1\frac{3}{12}-2\frac{8}{12}=-3\frac{11}{12}[/tex]
