Cześć ;-)
Zadanie 8
[tex]\sqrt[3]{24}+\sqrt[3]{81}-\sqrt[3]{192}=\\\\=\sqrt[3]{8\cdot3}-\sqrt[3]{27\cdot3}-\sqrt[3]{64\cdot3}=\\\\=\sqrt[3]{2^3\cdot3}+\sqrt[3]{3^3\cdot3}-\sqrt[3]{4^3\cdot3}=\\\\=2\sqrt[3]3+3\sqrt[3]3-4\sqrt[3]3=\sqrt[3]3\\\\\huge\boxed{\text{Odp}. \ \text{D}}[/tex]
Zadanie 9
[tex]\sqrt[5]{\frac{15}{8}}:\sqrt[5]{\frac{15}{4}}=\sqrt[5]{\frac{15}{8}:\frac{15}{4}}=\sqrt[5]{\frac{15}{8}\cdot\frac{4}{15}}=\sqrt[5]{\frac{1}{2}}\\\\\huge\boxed{\text{Odp}. \ \text{B}}[/tex]
Zadanie 10
[tex]\sqrt[3]{\frac{4}{5}}\cdot\sqrt[3]{-\frac{2}{25}}=\sqrt[3]{\frac{4}{5}\cdot(-\frac{2}{25})}=\sqrt[3]{-\frac{8}{125}}=-\frac{2}{5}\\\\\huge\boxed{\text{Odp}. \ \text{D}}[/tex]
Pozdrawiam!
