[tex]\dfrac{(1\frac{1}{12}+2\frac{5}{32}+\frac{1}{24})\cdot9\frac{3}{5}+2,13}{0,4}=\dfrac{(1\frac{2}{24}+\frac{1}{24}+2\frac{5}{32})\cdot\frac{48}{5}+2\frac{13}{100}}{\frac{2}{5}}=\\=\dfrac{(1\frac{3}{24}+2\frac{5}{32})\cdot\frac{48}{5}+2\frac{13}{100}}{\frac{2}{5}}=\dfrac{(1\frac{1}{8}+2\frac{5}{32})\cdot\frac{48}{5}+2\frac{13}{100}}{\frac{2}{5}}=[/tex]
[tex]=\dfrac{(1\frac{4}{32}+2\frac{5}{32})\cdot\frac{48}{5}+2\frac{13}{100}}{\frac{2}{5}}=\dfrac{3\frac{9}{32}\cdot\frac{48}{5}+2\frac{13}{100}}{\frac{2}{5}}=\dfrac{\frac{105}{32}\cdot\frac{48}{5}+2\frac{13}{100}}{\frac{2}{5}}=\\\dfrac{\frac{63}{2}+2\frac{13}{100}}{\frac{2}{5}}=\dfrac{31\frac{1}{2}+2\frac{13}{100}}{\frac{2}{5}}=\dfrac{31\frac{50}{100}+2\frac{13}{100}}{\frac{2}{5}}=\dfrac{31\frac{53}{100}}{\frac{2}{5}}=31\frac{53}{100}:\frac{2}{5}=[/tex]
[tex]=31\frac{53}{100}:\frac{2}{5}=\frac{3153}{100}\cdot\frac{5}{2}=\frac{3153}{40}=78\frac{33}{40}[/tex]
[tex]\dfrac{2,625-\frac23\cdot2\frac5{14}}{(3\frac1{12}+4,375):19\frac89}=\dfrac{2\frac58-\frac23\cdot\frac{33}{14}}{(3\frac1{12}+4\frac38):\frac{179}9}=\dfrac{2\frac58-\frac{11}{7}}{(3\frac{2}{24}+4\frac{9}{24}):\frac{179}{9}}=\\=\dfrac{2\frac{5}{8}-1\frac{4}{7}}{7\frac{11}{24}:\frac{179}{9}}=\dfrac{2\frac{35}{56}-1\frac{32}{56}}{\frac{179}{24}\cdot\frac{9}{179}}=\dfrac{1\frac{3}{56}}{\frac{3}{8}}=1\frac{3}{56}:\frac{3}{8}=\frac{59}{56}\cdot\frac{8}{3}=\frac{59}{56}\cdot\frac{8}{5}=\frac{59}{35}=1\frac{24}{35}[/tex]
