Odpowiedź:
[tex]a)\frac{1}{7}+\frac{5}{14 }=\frac{2}{14}+\frac{5}{14}=\frac{7}{14}=\frac{1}{2} \\\\b)\frac{3}{4}+\frac{5}{12} =\frac{9}{12}+\frac{5}{12}=\frac{14}{12}=1\frac{2}{12}=1\frac{1}{6} \\\\c) \frac{8}{9}-\frac{5}{18}=\frac{16}{18}-\frac{5}{18}=\frac{11}{18} \\\\d) \frac{1}{3}+ \frac{3}{4}= \frac{4}{12}+ \frac{9}{12}= \frac{13}{12}=1 \frac{1}{12} \\\\e) \frac{3}{5}-\frac{1}{2}= \frac{6}{10}-\frac{5}{10}= \frac{1}{10} \\\\[/tex]
[tex]f) 1\frac{1}{2}- \frac{1}{3}= \frac{3}{2}-\frac{1}{3}=\frac{9}{6}-\frac{2}{6}=\frac{7}{6}=1 \frac{1}{6\\\\} \\\\g) 1\frac{1}{2}- \frac{1}{3}= \frac{3}{2}+\frac{3}{8}= \frac{24}{16}+ \frac{6}{16}= \frac{30}{16}=1\frac{14}{16}=1\frac{7}{8} \\\\h)1\frac{1}{3}- \frac{2}{9}=\frac{4}{3}- \frac{2}{9}=\frac{36}{27}-\frac{6}{27}= \frac{30}{27}=1 \frac{1}{9} \\\\i)2\frac{3}{5}- \frac{7}{10}=\frac{13}{5}-\frac{7}{10}=\frac{130}{50}- \frac{35}{50}=\frac{95}{50}=1\frac{9}{10}[/tex]
[tex]j)\frac{5}{6}- \frac{1}{4}= \frac{20}{24}-\frac{6}{24}=\frac{14}{24}= \frac{7}{12} \\\\k) 1\frac{1}{6}- \frac{7}{9}= \frac{7}{6}- \frac{7}{9}= \frac{63}{54}- \frac{42}{54}=\frac{21}{54}=\frac{7}{18} \\\\l) 2\frac{3}{8}-1 \frac{5}{6}=\frac{19}{8}-\frac{11}{6}= \frac{114}{48}- \frac{88}{48}=\frac{26}{48}= \frac{13}{24}[/tex]
