Odpowiedź:
[tex]f)\ \ 1\frac{5}{7}:6=\frac{\not12^2}{7}\cdot\frac{1}{\not6_{1}}=\frac{2}{7}\\\\\\g)\ \ 6\frac{1}{2}:3\frac{1}{4}=\frac{13}{2}:\frac{13}{4}=\frac{\not13^1}{\not2_{1}}\cdot\frac{\not4^2}{\not13_{1}}=\frac{2}{1}=2\\\\\\h)\ \ 7\frac{1}{3}:2\frac{2}{5}=\frac{22}{3}:\frac{12}{5}=\frac{\not22^1^1}{3}\cdot\frac{5}{\not12_{6}}=\frac{55}{18}=3\frac{1}{18}[/tex]
[tex]i)\ \ \not2^1\cdot\frac{13\cdot4}{\not8_{4}}=\frac{13\cdot\not4^1}{\not4_{1}}=13\\\\\\j)\ \ 8\frac{3}{4}\cdot\frac{4}{7}\cdot3=\frac{\not35^5}{\not4_{1}}\cdot\frac{\not4^1}{\not7_{1}}\cdot3=5\cdot3=15\\\\\\k)\ \ 2\frac{1}{7}\cdot7\cdot2\frac{2}{5}=\frac{15}{\not7_{1}}\cdot\not7^1\cdot\frac{12}{5}=\not15^3\cdot\frac{12}{\not5_{1}}=3\cdot12=36[/tex]
[tex]l)\ \ \not4^1\cdot\frac{15\cdot9}{\not12_{3}}=\frac{\not15^5\cdot9}{\not3_{1}}=5\cdot9=45[/tex]
