a)
[tex]{3}^{3} = 27[/tex]
[tex] {0}^{250} = 0[/tex]
[tex] {11}^{2} = 121[/tex]
[tex]{( \frac{1}{2})}^{4} = \frac{1}{16} [/tex]
[tex] {( - 2 \frac{1}{4} )}^{2} = {( - \frac{9}{4}) }^{2} = \frac{81}{16} = 5 \frac{1}{16} [/tex]
[tex] {( - 0.6)}^{} = - 0.216[/tex]
b)
[tex] {( - 2)}^{3} = - 8[/tex]
[tex] {( - 0.2)}^{3} = - 0.008[/tex]
[tex] {12}^{2} = 144[/tex]
[tex] {( - \frac{1}{3}) }^{2} = \frac{1}{9} [/tex]
[tex] {( - 1 \frac{1}{2}) }^{3} = {( - \frac{3}{2}) }^{3} = - \frac{27}{8} = - 3 \frac{3}{8} [/tex]
[tex] {(0.2)}^{5} = 0.00032[/tex]
c)
[tex] {(0.3)}^{2} = 0.09[/tex]
[tex] {( - 0.1)}^{6} = 0.000001[/tex]
[tex] {13}^{2} = 169[/tex]
[tex] {( \frac{3}{4}) }^{3} = \frac{27}{64} [/tex]
[tex] {(3 \frac{1}{3}) }^{0} = 1[/tex]
[tex] {(1.3)}^{2} = 1.69[/tex]
Mam nadzieję, że pomogłam! ❤️
Cześć ;-)
a)
[tex]3^3=3\cdot3\cdot3=27\\\\0^{250}=0\\\\11^2=11\cdot11=121\\\\(\frac{1}{2})^4=\frac{1}{2}\cdot\frac{1}{2}\cdot\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{16}\\\\(-2\frac{1}{4})^2=(-\frac{9}{4})^2=-\frac{9}{4}\cdot(-\frac{9}{4})=\frac{81}{16}=5\frac{1}{!6}\\\\(-0,6)^3=(-\frac{3}{5})\cdot(-\frac{3}{5})\cdot(-\frac{3}{5})=-\frac{27}{125}[/tex]
b)
[tex](-2)^3=-2\cdot(-2)\cdot(-2)=-8\\\\(-0,2)^3=-\frac{1}{5}\cdot(-\frac{1}{5})\cdot(-\frac{1}{5})=-\frac{1}{125}\\\\12^2=12\cdot12=144\\\\(-\frac{1}{3})^2=-\frac{1}{3}\cdot(-\frac{1}{3})=\frac{1}{9}\\\\(-1\frac{1}{2})^3=(-\frac{3}{2})^3=-\frac{3}{2}\cdot(-\frac{3}{2})\cdot(-\frac{3}{2})=-\frac{27}{8}=-3\frac{3}{8}\\\\0,2^5=0,2\cdot0,2\cdot0,2\cdot0,2\cdot0,2=0,00032[/tex]
c)
[tex](0,3)^2=0,3\cdot0,3=0,09\\\\(-0,1)^6=-0,1\cdot(-0,1)\cdot(-0,1)\cdot(-0,1)\cdot(-0,1)\cdot(-0,1)=0,000001\\\\13^2=13\cdot13=169\\\\(\frac{3}{4})^3=\frac{3}{4}\cdot\frac{3}{4}\cdot\frac{3}{4}=\frac{27}{64}\\\\(3\frac{1}{3})^0=1\\\\(1,3)^2=1,3\cdot1,3=1,69[/tex]
