[tex]f(x) = x^{2}+5x-6\\\\a = 1, \ \ b = 5, \ \ c = -6\\\\f(x) = a(x-p)^{2}+q \ - \ postac \ kanoniczna\\\\p = \frac{-b}{2a} = \frac{-5}{2\cdot1}=\frac{-5}{2} = -2,5\\\\q = \frac{-\Delta}{4a} =\frac{-(b^{2}-4ac)}{4a}= \frac{-[5^{2}-4\cdot1\cdot(-6)]}{4\cdot1} = \frac{-(25+24)}{4} = \frac{-49}{4} = -12,25\\\\\underline{f(x) = (x+2,5)^{2}-12,25}[/tex]
