Odpowiedź :
Odpowiedź:
[tex](\frac{2}{3})^2=\frac{2^2}{3^2}=\frac{4}{9}\\\\(-\frac{2}{3})^3=-(\frac{2}{3})^3=-\frac{2^3}{3^3}=-\frac{8}{27}\\\\(\frac{2}{3})^4=\frac{2^4}{3^4}=\frac{16}{81}\\\\(\frac{2}{5})^5=\frac{2^5}{5^5}=\frac{32}{3125}\\\\(-\frac{2}{3})^6=(\frac{2}{3})^6=\frac{2^6}{3^6}=\frac{64}{729}\\\\(2\frac{1}{6})^2=(\frac{13}{6})^2=\frac{13^2}{6^2}=\frac{169}{36}=4\frac{25}{36}\\\\(-1\frac{1}{9})^2=(-\frac{10}{9})^2=(\frac{10}{9})^2=\frac{10^2}{9^2}=\frac{100}{81}=1\frac{19}{81}[/tex]
[tex](2\frac{1}{7})^2=(\frac{15}{7})^2=\frac{15^2}{7^2}=\frac{225}{49}=4\frac{29}{49}\\\\(-1\frac{1}{11})^2=(-\frac{12}{11})^2=(\frac{12}{11})^2=\frac{12^2}{11^2}=\frac{144}{121}=1\frac{23}{121}\\\\(3\frac{1}{3})^2=(\frac{10}{3})^2=\frac{10^2}{3^2}=\frac{100}{9}=11\frac{1}{9}[/tex]
Odpowiedź:
Szczegółowe wyjaśnienie:
(2/3)^2=2/3*2/3=4/9
(-2/3)^3= -2/3*(-2/3)*(-2/3)= -8/27
(2/3)^4=2/3*2/3*2/3*2/3=16/81
(2/5)^5=2/5*2/5*2/5*2/5*2/5=32/625
(-2/3)^6=-2/3*(-2/3)*(-2/3)*-2/3)*-2/3)*(-2/3)=64/729
(2 1/6)^2=(13/6)^2=13/6*13/6=169/36=4 25/36
(-1 1/9)^2=(-10/9)^2= -10/9*(-10/9)=100/81=1 19/81
(2 1/7)^2=(15/7)^2=15/7*15/7=225/49=4 29/49
(-1 1/11)^2=(-12/11)^2= -12/11* (-2/11)=144/121=1 23/121
(3 1/3)^2=(10/3)^2=10/3*10/3=100/9=11 1/9