Odpowiedź :
[tex]d = a\sqrt{2}\\\\A)\\a\sqrt{2} = 2,5\sqrt{2} \ \ /:\sqrt{2}\\\\a = 2,5 \ cm\\\\B)\\a\sqrt{2} = 4 \ \ /:\sqrt{2}\\\\a = \frac{4}{\sqrt{2}}\cdot\frac{\sqrt{2}}{\sqrt{2}}=\frac{4\sqrt{2}}{2} = 2\sqrt{2}\\\\a = 2\sqrt{2} \ cm[/tex]
[tex]d = a\sqrt{2}\\\\A)\\a\sqrt{2} = 2,5\sqrt{2} \ \ /:\sqrt{2}\\\\a = 2,5 \ cm\\\\B)\\a\sqrt{2} = 4 \ \ /:\sqrt{2}\\\\a = \frac{4}{\sqrt{2}}\cdot\frac{\sqrt{2}}{\sqrt{2}}=\frac{4\sqrt{2}}{2} = 2\sqrt{2}\\\\a = 2\sqrt{2} \ cm[/tex]