[tex]\frac{1}{x-3} + \frac{x}{6-2x} -1 = 0[/tex]
[tex] \frac{1}{x - 3} + \frac{x}{ - 2(x - 3)} = 1[/tex]
[tex] \frac{1}{x - 3} - \frac{x}{2(x - 3)} = 1[/tex]
[tex] \frac{2}{2(x - 3)} - \frac{x}{2(x - 3)} = 1[/tex]
[tex] \frac{2 - x}{2(x - 3)} = 1 | \times 2(x - 3)[/tex]
2 - x = 2 (x - 3)
2 - x = 2x - 6
-3x = -8
[tex]x = \frac{8}{3} [/tex]
