Odpowiedź:
[tex]1\frac{1}{6}+2\frac{2}{3}=1\frac{1}{6}+2\frac{4}{6}=3\frac{5}{6}\\\\\\4\frac{1}{4}-2\frac{2}{3}=4\frac{3}{12}-2\frac{8}{12}=3\frac{15}{12}-2\frac{8}{12}=1\frac{7}{12}\\\\\\4\frac{3}{7}+2\frac{2}{3}=4\frac{9}{21}+2\frac{14}{21}=6\frac{23}{21}=7\frac{2}{21}\\\\\\5\frac{1}{9}-1\frac{5}{6}=5\frac{2}{18}-1\frac{15}{18}=4\frac{20}{18}-1\frac{15}{18}=3\frac{5}{18}[/tex]
[tex]1\frac{2}{5}+3\frac{4}{10}+2\frac{1}{2}=1\frac{4}{10}+3\frac{4}{10}+2\frac{5}{10}=6 \frac{13}{10}=7\frac{3}{10}[/tex]
