[tex]dane:\\m = 1 \ kg\\T_1 = 15^{o}C\\T_2 = 100^{o}C\\\Delta T = T_2 - T_1 = 100^{o}C - 15^{o}C = 85^{o}C\\c = 4200\frac{J}{kg\cdot ^{o}C}\\szukane:\\Q = ?\\\\Q = c\cdot m\cdot \Delta T\\\\Q = 4200\frac{J}{kg\cdit ^{o}C}\cdot1 \ kg\cdot85^{o}C\\\\Q = 357 \ 000 \ J = 357 \ kJ[/tex]
