Zadanie 3 :
[tex]P=\frac{d_1\cdot d_2}{2}\\\\d_1=10 \ cm\\\\d_2=1,12\cdot10=11,2 \ cm\\\\P=\frac{10\cdot11,2}{2}=\frac{112}{2}=\boxed{56 \ cm^2}[/tex]
Zadanie 4 :
[tex]6a=60 \ cm \ \ |:6\\\\a=10 \ cm\\\\P=6\cdot\frac{a^2\sqrt3}{4}=6\cdot\frac{10^2\sqrt3}{4}=6\cdot25\sqrt3=\boxed{150\sqrt3 \ cm^2}[/tex]
