[tex]P_c=2\cdot(ab+bc+ac)\\\\V=a\cdot b\cdot c\\\\a=3 \ m, \ b=5 \ m, \ c=6 \ m\\\\P_c=2\cdot(3\cdot5+5\cdot6+3\cdot6)=2\cdot(15+30+18)=2\cdot63=\boxed{126 \ m^2}\\\\V=3\cdot5\cdot6=15\cdot6=\boxed{90 \ m^3}[/tex]
Odpowiedź:
a = 3m
b = 5m
h =6m
V = abh = 90 m³
Pc = 2ab+2bh+2ah = 30m²+60m²+36m² = 126m²
Szczegółowe wyjaśnienie:
