Odpowiedź :
[tex]a = 8 \ cm\\b = 8\sqrt{3} \ cm\\d = ?\\\\a^{2}+b^{2} = d^{2}\\\\8^{2}+(8\sqrt{3})^{2} = d^{2}\\\\64 + 192 = d^{2}\\\\256 =d^{2}\\\\d = \sqrt{256}\\\\d = 16 \ cm \ - \ przekatna \ prostokata[/tex]
[tex]bok\ prostokata:\ a=8\ cm \\bok\ prostokata:\ b=8\sqrt{3}\ cm\\przekatna:\ d=?\\\\d^2=a^2+b^2\\\\d^2=8^2+(8\sqrt{3})^2\\\\d^2=64+64*3\\\\d^2=64+192\\\\d^2=256\\\\d=\sqrt{256}\\\\d=16\ cm[/tex]
