Odpowiedź:
zad15
[tex]\frac{16+4\sqrt[3]{5} }{4} =4+\sqrt[3]{5}[/tex]
zad16
√6(3-√6)=3√6-(√6)²=3√6-6
zad17
[tex]\sqrt{54} =\sqrt{9*6} =3\sqrt{6}[/tex]
zad18
[tex]\sqrt[3]{96} =\sqrt[3]{8*12} =2\sqrt[3]{12}[/tex]
zad19
[tex]7\sqrt{2} +\sqrt{50} -\sqrt{32} =7\sqrt{2} +5\sqrt{2} -4\sqrt{2} =12\sqrt{2}-4\sqrt{2}=8\sqrt{2}[/tex]
Szczegółowe wyjaśnienie:
