Odpowiedź:
A(-5; 4), B(0; -1), C(7;6)
|AB| = pierw z (x2-x1)^2+(y2-y1)^2
|AB| = pierw z (0-(-5))^2 + (-1-4)^2
|AB| = pierw z 25+25
|AB| = 5 pier z 2
|BC| = pier z (7-0)^2+(6-(-1))^2
|BC| = pier z 49+49
|BC| = 7 pier z 2
|CA| = pier z (7-(-5))^2 + (6-4)^2
|CA| = pier z 12^2 + 2^2
|CA| = pier 144+4
|CA| = 2 pier 37
Szczegółowe wyjaśnienie:
