Odpowiedź:
[tex]\begin{cases}x(1-2x)-y(1-y)=(y-\sqrt{2}x)(y+\sqrt{2}x)+3\\2x-(2y-\frac{1}{4})^2+16\frac{1}{16}=(2y+3)(3-2y)\end{cases}\\\\\\\begin{cases}x-2x^{2}-y+y^2=y^2-2x^2+3\\2x-(4y^2-y+\frac{1}{16})+16\frac{1}{16}=(3+2y)(3-2y)\end{cases}\\\\\\\begin{cases}x-2x^2-y+y^2-y^2+2x^2=3\\2x-4y^2+y-\frac{1}{16}+16\frac{1}{16}=9-4y^2\end{cases}\\\\\\\begin{cases}x-y=3\\2x-4y^2+y+16=9-4y^2\end{cases}\\\\\\\begin{cases}x-y=3\\2x-4y^2+y+4y^2=9-16\end{cases}[/tex]
[tex]+\begin{cases}x-y=3\\2x+y=-7\end{cases}\\--------\\3x=-4\ \ /:3\\\\x=-\frac{4}{3}\\\\\\-\frac{4}{3}-y=3\\\\-y=3+\frac{4}{3}\\\\-y=\frac{9}{3}+\frac{4}{3}\\\\-y=\frac{13}{3}\ \ /\cdot(-1)\\\\y=-\frac{13}{3}\\\\\\\begin{cases}x=-\frac{4}{3}\\y=-\frac{13}{3}\end{cases}[/tex]
