Witam.
[tex]a) \: ( \frac{5}{3} - \frac{1}{3} + \frac{7}{3}) \times 3 = \frac{11}{3} \times \frac{3}{1} = \frac{11}{1} = 11[/tex]
[tex]b) \: ( \frac{11}{2} - \frac{5}{2} + \frac{15}{2} ) \times 2 = \frac{21}{2} \times \frac{2}{1} = \frac{21}{1} = 21[/tex]
[tex]c) \: 3 \frac{2}{3} + 3 \times 1 \frac{1}{3 } = 3 \frac{2}{3} + \frac{3}{1} \times \frac{4}{3} = 3 \frac{2}{3} + 4 = 7 \frac{2}{3} [/tex]
[tex]d) \: 3 \frac{1}{4} \times 4 - 2 \frac{3}{4} = \frac{13}{4} \times \frac{4}{1} - 2 \frac{3}{4} = 13 - 2 \frac{3}{4} = 10 \frac{1}{4} [/tex]
[tex]e) \: 2 \frac{1}{5} \times 5 - 4 \frac{2}{5} + 1 \frac{1}{5} = \frac{11}{5} \times \frac{5}{1} - 3 \frac{1}{5} = 11 - 3 \frac{1}{5} = 7 \frac{4}{5} [/tex]
[tex]f) \: 7 \frac{1}{2} - 3 + 2 \times \frac{3}{4} = 4 \frac{1}{2} + \frac{2}{1} \times \frac{3}{4} = 4 \frac{1}{2} + 1 \frac{1}{2} = 6[/tex]
[tex]g) \: 2 \frac{1}{2} \times 3 + 4 \times 1 \frac{1}{2} = \frac{5}{2} \times \frac{3}{1 } + \frac{4}{1} \times \frac{3}{2 } = \frac{15}{4} + 6 = 3 \frac{3}{4} + 6 = 9 \frac{3}{4} [/tex]
[tex]h) \: 2 \frac{1}{4} \times 2 + 3 \frac{3}{4} = \frac{9}{4} \times \frac{2}{1} + 3 \frac{3}{4} = \frac{9}{2} + 3\frac{3}{4} = 8 \frac{1}{2} + 3 \frac{3}{4} = 8 \frac{2}{4} + 3 \frac{3}{4} = 11 \frac{5}{4} = 12 \frac{1}{4} [/tex]
[tex]i) \: 9 - 1 \frac{3}{5} \times 4 = 9 - \frac{8}{5} \times \frac{4}{1} = 9 - \frac{32}{5} = 9 - 6 \frac{2}{5} = 2 \frac{3}{5} [/tex]
Pozdrawiam,
Michał
