Oblicz (pamiętaj o kolejności wykonywania działań).
a) [tex](3+4)^{2}[/tex]
b) [tex]3^{2} +4^{2}[/tex]
c) [tex]4^{2} -(-3)^{3} -10^{3}[/tex] · [tex]0,1[/tex]
d) [tex]\frac{1}{4} ^{2} +2^{3}[/tex] · [tex] (-\frac{1}{2} ^{3}[/tex])
e) [tex](\frac{2}{3} )^{2}[/tex] · [tex]\frac{3}{4}^{2}[/tex] [tex]-(-\frac{1}{2} )^{2}[/tex]
f) [tex]\frac{2^{3} }{5} +\frac{2}{5^{3} } +(\frac{2}{5} )^{3}[/tex]

PLSS!!! Z OBLICZENIAMI!!! z gory dzieki <3 (daje naj jak cos)


Odpowiedź :

Odpowiedź:

a) [tex](3+4)^{2} =7^{2} =49[/tex]

b) [tex]3^{2} +4^{2} =9+16=25[/tex]

c) [tex]4^{2} - (-3)^{3} -10^{3} *0,1=16-(-27)-1000*0,1= 16+27-100=-57[/tex]

d)  [tex]\frac{1}{4}^{2} + 2^{3}* (-\frac{1}{2})^{3}= \frac{1}{4} +8*(-\frac{1}{8})=-\frac{3}{4} \\[/tex]

e) [tex](\frac{2}{3})^{2} *\frac{3^{2} }{4} - (-\frac{1}{2})^{2}=\frac{4}{9} *\frac{9}{4} -\frac{1}{4} = \frac{3}{4}[/tex]

f) [tex]\frac{2^{3}}{5} +\frac{2}{5^{3} } +(\frac{2}{5}) ^{3}= \frac{8}{5} +\frac{2}{125} +\frac{8}{125} =\frac{200}{125} +\frac{2}{125} +\frac{8}{125} = \frac{210}{125} =\frac{42}{25}=1\frac{17}{25}[/tex]

Szczegółowe wyjaśnienie: