Odpowiedź:
[tex]dane:\\m=0,25kg\\h_1=1,1m\\h_2=0,5m\\\\szukane:\\E_{p_2}=?\\E_{k_2}=?\\E_p=mgh\\E_k=\frac{mv^2}{2}\\ZZE: E_p+E_k=E_m=const.\\\\rozwiazanie:\\Na~~stole:\\E_{p_1}=mgh_1=0,25kg\cdot 10\frac{m}{s^2}\cdot 1,1m=2,75J\\E_{k_1}=0~~(cialo ~~ nie~~posiada~~predkosci)\\E_m=2,75J+0=2,75J\\\\Na ~~wysoko\'sci~~0,5m:\\E_{p_2}=mgh_2=0,25kg\cdot 10\frac{m}{s^2}\cdot 0,5m=1,25J\\E_{k_2}=E_m-E_{p_2}=2,75J-1,25J=1,5J[/tex]
Wyjaśnienie:
