Odpowiedź:
[tex] \frac{ { {(2}^{4}) }^{7} }{ {2}^{3} \times {2}^{5} } = \frac{ {2}^{28} }{ {2}^{8} } = {2}^{20} [/tex]
[tex]4 \times {2}^{8} = {2}^{2} \times {2}^{8} = {2}^{10} [/tex]
[tex] { {(4}^{4}) }^{3} = {4}^{12} = {( {2}^{2}) }^{12} = {2}^{24} [/tex]
[tex] {32}^{3} = { {(2}^{5}) }^{3} = {2}^{15} [/tex]
