5.7
[tex]g)\\|\sqrt{7}-2|\cdot|-\sqrt{7}-2|=(\sqrt{7}-2)\cdot[-(-\sqrt{7}-2)] = (\sqrt{7}-2)(\sqrt{7}+2) = 7-4=3\\\\h)\\ |5-3\sqrt{3}|\cdot|5+3\sqrt{3}|=[-(5-3\sqrt{3})]\cdot(5+3\sqrt{3}) = (3\sqrt{3}-5)(3\sqrt{3}+5) = 27-25 = 2[/tex]
5.8
[tex]a) \ |\sqrt{2}+\sqrt{5}-2| =\sqrt{2}+\sqrt{5}-2\\\\b) \ |5-2\sqrt{3}-\sqrt{5}| = -(5-2\sqrt{3}-\sqrt{5}) = 2\sqrt{3}+\sqrt{5}-5\\\\c) \ |\sqrt{10}+\sqrt{17} -\sqrt{47}| = \sqrt{10}+\sqrt{17}-\sqrt{47}\\\\d) \ |\sqrt{99}-3-\sqrt{50}|=-(\sqrt{99}-3-\sqrt{50}) = 3+\sqrt{50}-\sqrt{99}[/tex]
