Odpowiedź:
[tex]5 \sqrt{27} - 2 \sqrt{48} + 2 \sqrt{12} = 5 \sqrt{9 \times 3} - 2 \sqrt{16 \times 3} + 2 \sqrt{4 \times 3} = 5 \times 3 \sqrt{3} - 2 \times 4 \sqrt{3} + 2 \times 2 \sqrt{3} = 15 \sqrt{3} - 8 \sqrt{3} + 4 \sqrt{3} = 7 \sqrt{3} + 4 \sqrt{3} = 11 \sqrt{3} [/tex]
