[tex]Zadaie\\\\e=10\sqrt{3}\\f=16\\P=40\sqrt{6} \\\\P=\frac{1}{2}\cdot e\cdot f\cdot sin\phi \\\\\frac{1}{2}\cdot10\sqrt{6} \cdot 16\cdot sin\phi=40\sqrt{6}\\\\80\sqrt{6}\cdot sin\phi=40\sqrt{6}\ \ \mid:(80\sqrt{6})\\\\sin\phi=\frac{1}{2}\\\\\phi=30^o\\\\Odp.\ A[/tex]
