[tex]Zadanie\ 1\\\\(\frac{3}{5})^2=\frac{9}{25}\\\\\frac{3^2}{5}=\frac{9}{5}=\frac{45}{25}\\\\ \frac{3}{5^2}=\frac{3}{25}\\\\Jezeli\ ulamki\ maja\ taki\ sam\ mianownik,\ to\ mniejszy\ jest\ ten,\ ktory\ ma\\\\mniejszy\ licznik\\\\\frac{3}{5^2}<(\frac{3}{5})^2< \frac{3^2}{5}\\\\Zadanie\ 2\\\\\frac{2}{3}+[(-\frac{1}{3})^2+(-\frac{1}{3})^2]: \frac{1}{3}=\frac{2}{3}+(\frac{1}{9}+\frac{1}{9})\cdot3=\frac{2}{3}+\frac{2}{\not9_3}\cdot\not3^1= \frac{2}{3}+\frac{2}{3}=\frac{4}{3}=1\frac{1}{3}[/tex]
