[tex]Zadanie\\\\xy+a=b\ \ \mid-a\\\\xy=b-a\ \ \mid:y\\\\x=\frac{b-a}{y}\\\\\\Zal.y\ne0[/tex]
[tex]xy + a = b\\\\xy = b-a \ \ /:y\\\\x = \frac{b-a}{y}[/tex]
