[tex]zad.5\\\\a)~~\sqrt[3]{1} =\sqrt[3]{1^{3} }=1\\\\b)~~-\sqrt[3]{1} =-\sqrt[3]{1^{3} }=-1\\\\c)~~\sqrt[3]{-1} =\sqrt[3]{(-1)^{3} }=-1\\\\d)~~\sqrt[3]{0} =0\\\\e)~~\sqrt[3]{27} =\sqrt[3]{3^{3} } =3\\\\f)~~\sqrt[3]{-8} =\sqrt[3]{(-2)^{3} }=-2\\\\1+(-1)+(-1)+0+3+(-2)=-4+4=0\\\\TAK~~suma~~wszystkich~~wynikow~~wynosi~~0.\\\\korzytalam~~ze~~wzoru:\\\\\sqrt[n]{x^{n} } =(x^{n} )^{\frac{1}{n} } =x^{n\cdot \frac{1}{n} } =x^{1} =x[/tex]
