Odpowiedź:
Zadanie 1
[tex]a) \frac{ {9}^{2} }{9} = \frac{9 \times 9}{9} = \frac{81}{9} = 9[/tex]
[tex]b) \frac{( - 4) {}^{3} }{4} = \frac{ - 4 \times ( - 4) \times ( - 4)}{4} = \frac{ - 64}{4} = - 16[/tex]
[tex]c) \frac{3}{ {( - 3)}^{?2} } = \frac{3}{ - 3 \times ( - 3)} = \frac{3}{9} [/tex]
[tex]d) \frac{ { - 2}^{6} }{32} = \frac{ - 2 \times ( - 2) \times ( - 2) \times ( - 2) \times ( - 2) \times ( - 2)}{32} = \frac{64}{32} = 2[/tex]
Zadanie 2
[tex]a)( - 2 {)}^{3} = ( - 2) \times ( - 2) \times ( - 2) = - 8[/tex]
[tex]b) {( - 9)}^{0} = 1[/tex]
[tex]c)( - 1.6) {}^{2} = - 1.6 \times ( - 1.6) = 2.56[/tex]
[tex]d) - 0. {1}^{5} = - 0.1 \times ( - 0.1) \times ( - 0.1) \times ( - 0.1) \times ( - 0.1) = - 0.00001[/tex]
[tex]e) - ( - 0.5) {}^{3} = 0.125[/tex]
Zadanie 3
[tex] {5}^{3} = 5 \times 5 \times 5 [/tex]
Zadanie 4
[tex]( \frac{3}{4} {)}^{3} = \frac{3}{4} \times \frac{3}{4} \times \frac{3}{4} = \frac{27}{64} [/tex]
Zadanie 5
[tex] - 4 \frac{1}{2} = 16 \frac{1}{4} [/tex]
Zadanie 6
[tex] \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} = ( \frac{1}{4} {)}^{4} [/tex]
Zadanie 7
D
Zadanie 8
tego zadanie niewiem sorry
Zadanie 9
[tex]a) = ( - {15)}^{6} = + [/tex]
[tex]b) { - 107}^{8} = - [/tex]
[tex]c) - ( - \frac{1}{8} ) {}^{11} = + [/tex]
[tex]d) \: niewim \: sorry[/tex]
Pozdrawiam.
