Odpowiedź:
[tex]\frac{y}{x} =p\\p=1\\\\\frac{xy}{y+x} =f\\\\\ f=0,24m\\x=?\\y=?\\\\[/tex]
[tex]\\\frac{y}{x} = 1 //*x\\y = x\\\\\frac{xy}{y+x}=f\\\frac{xy}{y+x}=0,24\\\frac{x^{2} }{2x} =0,24 //*2x\\x^{2} = 0,48x\\x^{2} -0,48x =0\\x(x-0,48)=0\\x=0 \\ lub \\x=0,48\\\\[/tex]
x=0,48
y=0,48
